Solar Incident Energy Based on Geographic Location Calculator

Accurately calculating solar incident energy based on geographic location is critical for optimizing solar energy systems. This calculation determines the amount of solar radiation a specific location receives, influencing system design and efficiency.

This article explores the technical methodologies, formulas, and practical applications of solar incident energy calculations. It provides detailed tables, real-world examples, and an AI-powered calculator to assist professionals in precise solar energy assessment.

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  • Latitude: 34.05, Longitude: -118.25, Date: 2024-06-21, Time: 12:00
  • Latitude: 51.51, Longitude: -0.13, Date: 2024-12-21, Time: 15:00
  • Latitude: -33.87, Longitude: 151.21, Date: 2024-03-21, Time: 09:00
  • Latitude: 40.71, Longitude: -74.01, Date: 2024-09-23, Time: 18:00

Comprehensive Tables of Solar Incident Energy by Geographic Location

Solar incident energy varies significantly with latitude, season, and atmospheric conditions. The following tables summarize average daily solar radiation values (kWh/m²/day) for various global locations, based on data from the National Renewable Energy Laboratory (NREL) and the Solar Radiation Data Manual.

LocationLatitude (°)Longitude (°)Average Daily Solar Radiation (kWh/m²/day)Peak Sun HoursTypical Atmospheric Conditions
Los Angeles, USA34.05-118.255.755.75Clear, Mediterranean
London, UK51.51-0.132.902.90Cloudy, Temperate
Sydney, Australia-33.87151.214.804.80Clear, Subtropical
New York City, USA40.71-74.014.204.20Variable, Temperate
Dubai, UAE25.2055.276.506.50Clear, Desert
Reykjavik, Iceland64.13-21.901.201.20Cloudy, Arctic
São Paulo, Brazil-23.55-46.635.005.00Humid Subtropical
Tokyo, Japan35.68139.694.504.50Temperate, Humid

These values represent average daily solar radiation on a horizontal surface, which is essential for estimating solar panel output and system sizing.

Fundamental Formulas for Solar Incident Energy Calculation

Calculating solar incident energy involves several key formulas that account for geographic location, solar angles, atmospheric conditions, and time. Below are the essential formulas with detailed explanations.

1. Solar Declination Angle (δ)

The solar declination angle represents the tilt of the Earth’s axis relative to the sun and varies throughout the year.

δ = 23.45 × sin(360 × (284 + n) / 365)
  • δ: Solar declination angle (degrees)
  • n: Day of the year (1 to 365)

This angle affects the sun’s height in the sky and thus the intensity of solar radiation.

2. Solar Zenith Angle (θz)

The solar zenith angle is the angle between the sun’s rays and the vertical direction at a specific location and time.

cos(θz) = sin(φ) × sin(δ) + cos(φ) × cos(δ) × cos(HRA)
  • θz: Solar zenith angle (degrees)
  • φ: Latitude of the location (degrees)
  • δ: Solar declination angle (degrees)
  • HRA: Hour angle (degrees), calculated as 15° × (Local Solar Time – 12)

The solar zenith angle is critical for determining the intensity of solar radiation on a surface.

3. Solar Incident Radiation on a Horizontal Surface (I)

The solar radiation incident on a horizontal surface can be estimated by:

I = I_sc × E_0 × cos(θz)
  • I: Solar irradiance on horizontal surface (W/m²)
  • I_sc: Solar constant ≈ 1367 W/m²
  • E_0: Eccentricity correction factor for Earth’s orbit
  • θz: Solar zenith angle (degrees)

The eccentricity correction factor E_0 is calculated as:

E_0 = 1 + 0.033 × cos(360 × n / 365)

This formula assumes clear sky conditions and does not account for atmospheric attenuation.

4. Air Mass (AM)

Air mass quantifies the path length of sunlight through the atmosphere relative to the shortest path (zenith).

AM = 1 / cos(θz)

For zenith angles greater than 60°, more complex models like Kasten and Young’s formula are used:

AM = 1 / (cos(θz) + 0.50572 × (96.07995 – θz)^(-1.6364))

5. Atmospheric Attenuation and Beam Radiation (Ib)

Solar radiation is attenuated by the atmosphere. The beam radiation on a horizontal surface is:

Ib = I_sc × E_0 × e^(-k × AM) × cos(θz)
  • Ib: Beam radiation on horizontal surface (W/m²)
  • k: Atmospheric extinction coefficient (typical range 0.1 to 0.4)
  • AM: Air mass

The extinction coefficient depends on atmospheric clarity, humidity, and pollution.

6. Total Solar Incident Energy (H)

Total daily solar incident energy (kWh/m²/day) is the integral of irradiance over daylight hours:

H = ∫ I(t) dt ≈ Σ I_i × Δt
  • H: Total daily solar energy (kWh/m²/day)
  • I(t): Instantaneous solar irradiance (W/m²)
  • Δt: Time interval (hours)

Numerical integration or summation over discrete time intervals is used in practical calculations.

Detailed Real-World Examples of Solar Incident Energy Calculation

Example 1: Calculating Solar Incident Energy in Los Angeles on June 21

Given:

  • Latitude (φ) = 34.05° N
  • Day of year (n) = 172 (June 21)
  • Local Solar Time = 12:00 (solar noon)
  • Atmospheric extinction coefficient (k) = 0.2 (clear sky)

Step 1: Calculate solar declination angle (δ)

δ = 23.45 × sin(360 × (284 + 172) / 365)
= 23.45 × sin(360 × 456 / 365)
= 23.45 × sin(449.04°)
≈ 23.45 × sin(89.04°)
≈ 23.45 × 0.9998 ≈ 23.44°

Step 2: Calculate hour angle (HRA)

HRA = 15 × (12 – 12) = 0°

Step 3: Calculate solar zenith angle (θz)

cos(θz) = sin(34.05) × sin(23.44) + cos(34.05) × cos(23.44) × cos(0)
= 0.560 × 0.398 + 0.829 × 0.917 × 1
= 0.223 + 0.760 = 0.983
θz = arccos(0.983) ≈ 10.2°

Step 4: Calculate eccentricity correction factor (E0)

E0 = 1 + 0.033 × cos(360 × 172 / 365)
= 1 + 0.033 × cos(169.04°)
= 1 + 0.033 × (-0.984)
= 1 – 0.0325 = 0.9675

Step 5: Calculate air mass (AM)

AM = 1 / cos(10.2°) = 1 / 0.983 = 1.017

Step 6: Calculate beam radiation (Ib)

Ib = 1367 × 0.9675 × e^(-0.2 × 1.017) × 0.983
= 1367 × 0.9675 × e^(-0.203) × 0.983
= 1367 × 0.9675 × 0.816 × 0.983
≈ 1367 × 0.776 ≈ 1060 W/m²

Step 7: Estimate total daily solar energy (H)

Assuming peak sun hours of 5.75 (from table), total daily energy:

H = Ib × Peak Sun Hours / 1000
= 1060 × 5.75 / 1000 = 6.10 kWh/m²/day

This value aligns well with typical measured data for Los Angeles in summer.

Example 2: Solar Incident Energy in London on December 21 at 3 PM

Given:

  • Latitude (φ) = 51.51° N
  • Day of year (n) = 355 (December 21)
  • Local Solar Time = 15:00
  • Atmospheric extinction coefficient (k) = 0.3 (cloudy conditions)

Step 1: Calculate solar declination angle (δ)

δ = 23.45 × sin(360 × (284 + 355) / 365)
= 23.45 × sin(360 × 639 / 365)
= 23.45 × sin(630.41°)
= 23.45 × sin(270.41°)
≈ 23.45 × (-0.9998) ≈ -23.44°

Step 2: Calculate hour angle (HRA)

HRA = 15 × (15 – 12) = 45°

Step 3: Calculate solar zenith angle (θz)

cos(θz) = sin(51.51) × sin(-23.44) + cos(51.51) × cos(-23.44) × cos(45)
= 0.782 × (-0.398) + 0.623 × 0.917 × 0.707
= -0.311 + 0.404 = 0.093
θz = arccos(0.093) ≈ 84.7°

Step 4: Calculate eccentricity correction factor (E0)

E0 = 1 + 0.033 × cos(360 × 355 / 365)
= 1 + 0.033 × cos(350.41°)
= 1 + 0.033 × 0.984
= 1 + 0.0325 = 1.0325

Step 5: Calculate air mass (AM)

Using Kasten and Young’s formula for θz > 60°:
AM = 1 / (cos(84.7) + 0.50572 × (96.07995 – 84.7)^(-1.6364))
= 1 / (0.093 + 0.50572 × (11.38)^(-1.6364))
= 1 / (0.093 + 0.50572 × 0.030)
= 1 / (0.093 + 0.015) = 1 / 0.108 = 9.26

Step 6: Calculate beam radiation (Ib)

Ib = 1367 × 1.0325 × e^(-0.3 × 9.26) × 0.093
= 1367 × 1.0325 × e^(-2.78) × 0.093
= 1367 × 1.0325 × 0.062 × 0.093
≈ 1367 × 0.006 ≈ 8.2 W/m²

Step 7: Estimate total daily solar energy (H)

Assuming peak sun hours of 2.9 (from table), total daily energy:

H = Ib × Peak Sun Hours / 1000
= 8.2 × 2.9 / 1000 = 0.024 kWh/m²/day

This low value reflects the short daylight and low sun angle typical of London in winter.

Additional Technical Considerations for Solar Incident Energy Calculations

  • Surface Tilt and Orientation: Incident energy varies with panel tilt angle (β) and azimuth (γ). Adjustments use the angle of incidence (θ) instead of zenith angle.
  • Diffuse and Reflected Radiation: Total solar radiation includes direct beam, diffuse sky radiation, and ground-reflected components, modeled by the Liu and Jordan or Perez models.
  • Atmospheric Conditions: Cloud cover, aerosols, and humidity significantly affect the extinction coefficient (k) and thus the incident energy.
  • Time Zone and Solar Time Corrections: Accurate hour angle calculation requires conversion from local standard time to solar time, accounting for longitude and equation of time.
  • Data Sources: Use of satellite-derived solar radiation databases (e.g., NASA SSE, PVGIS) enhances accuracy for specific locations.

Authoritative Resources and Standards

Understanding and accurately calculating solar incident energy based on geographic location is fundamental for solar energy system design, performance prediction, and optimization. This article provides the technical foundation and practical tools necessary for professionals in the renewable energy sector.